条件队列的唤醒机制探究

bf1,bf2是两个大小各为3的条件队列。3将要put进bf1，此时因为bf1已满而已调用wait()方法挂起线程,此时若对bf2()执行take()方法并调用notifyall()是否会唤醒wait()中的bf1？(对两个队列的操作存在于两个不同的线程中)

先上代码

public abstract class BaseBoundedBuffer<V>{

    private final V[] buf;
    private  int tail;
    private  int head;
    private  int count;

    protected BaseBoundedBuffer(int capacity) {
        this.buf = (V[]) new Object[capacity];
    }

    protected synchronized final void doPut(V v){
        buf[tail]=v;
        if (++tail==buf.length){
            tail=0;

        }
        ++count;
    }
    protected synchronized final V doTake(){
        V v=buf[head];
        buf[head]=null;
        if (++head == buf.length){
            head=0;
        }
        --count;
        return v;
    }
    public synchronized final boolean isFull(){
        return  count==buf.length;
    }
    public synchronized final boolean isEmpty(){
        return count==0;
    }



}

public class BoundedBuffer<V> extends BaseBoundedBuffer {
        private int id;
    protected BoundedBuffer(int capacity,int id) {
        super(capacity);
        this.id=id;
    }
    public synchronized void put(V v)throws InterruptedException{   //对条件队列执行增加元素的操作
        while (isFull()){
            System.out.println(id+"快睡了------put");
            wait();
            System.out.println(id+"醒了--------put");
        }
        doPut(v);
        System.out.println(id+"put"+v);
        notifyAll();
    }
    public synchronized V take() throws InterruptedException{    //对条件队列执行读取操作
        while (isEmpty()){
            System.out.println(id+"快睡了--------take");
            wait();
            System.out.println(id+"醒了----------take");
        }
        V v= (V) doTake();
        notifyAll();
        return v;

    }
}

public class BufferTest {
    public static void main(String[] args) throws InterruptedException {
        BoundedBuffer bf =new BoundedBuffer(3,1);
        BoundedBuffer bf2=new BoundedBuffer(3,2);
        bf2.put(9999999);
        new Thread(){
            public void run(){
                for (int i=0;i<4;i++){
                    try {
                        bf.put(i);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }
            }
        }.start();

        new Thread(){
            public void run(){

                    try {
                        System.out.println( bf2.take());

                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }

        }.start();
    }
}

执行结果如下
2put9999999
1put0
1put1
1put2
1快睡了------put
9999999

在执行结果第五行的时候便是上图所描述的情况(3想要put进bf1,但是因为已经full,bf1进入wait()状态),第六行输出了9999999,也就说明bf2执行了take()操作,同时也执行了notifyAll()方法，然而对bf1没有产生任何影响。
V v= (V) doTake(); notifyAll(); return v;

结果证明： 在使用条件队列时候，notifyAll()只会唤醒同一对象因执行wait()被挂起的线程